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In a fort 300 men had provisions for 90 days

WebSep 18, 2024 · Answer: 84 Days Step-by-step explanation: Remaining number of men = (300−50)=250. Remaining number of days = (90−20)days=70 days 300 men had provisions for 70 days 1 man had provisions for (300×70) days... [less men, more days] 250 men had provisions for 300×70/250 days =84 days... [more men, less days] WebAug 3, 2016 · nickunikkip9bq4c. ☆Hello friend☆. First 90 days were there but at present days are left 90-20= 70 days. There were 300 men but 50 men then left, Remaining one's= …

In a Fort, 300 soldiers had of food provision for 90 days.

WebSep 13, 2024 · Solution: The remaining food is sufficient for 300 men for (90-20)days=70 days. Remaining number of men= (300-50)=250. Let,the remaining food be sufficient for … Web60 days. Send all 160 soldiers out food foraging- 40 at a time- 20 forage for food while the others stand guard 3 to four hours, then they switch places. I would assume the garrison is near a fresh water resource ( lake, stream or river, and/or near the ocean. Assume two groups go out daily. buchanan county library https://boom-products.com

Solved A fort had provisions with 300 men for 90 days. After - Chegg

WebA fort had provisions with 300 men for 90 days. After 20 days 50 men left the fort. How long would the food last at the same rate? Question: A fort had provisions with 300 men for 90 … WebAfter some days, 300 more men joined the gar... - YouTube A garrison had provisions for 1500 men for 30 days. After some days, 300 more men joined the garrison. The provisions... extended fuel allowance

a fort had provisions for 300 men for 90 days, after 20 days,50 …

Category:A garrison had provisions for 1500 men for 30 days. After some days …

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In a fort 300 men had provisions for 90 days

1) A group of 120 men had provision for 200 days. After 5 days 30 men …

Weba fort had provisions for 300 men for 90 days, after 20 days,50 men left the fort how long would the food last at the same rate - Maths - Direct and Inverse Proportions WebA man can do a work in 3 days alone and a women can do the same work in 9 days alone. If both are work together in how many days they finished the same work. There are 8 mango trees in a straight line. The distance between each mango tree with other is 3 metres. What is the distance between the first and the eighth tree.

In a fort 300 men had provisions for 90 days

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WebOct 12, 2024 · In a fort, 300 men had provisions for 90 days. After 20 days, 50 men left the fort How long wo... Doubtnut. 2.72M subscribers. Subscribe. 15K views 4 years ago. To … WebA garrison of 500 men had provisions for 24 days. However, a reinforcement of 300 men arrived. The food will now last for (a) 18 days (b) 17 1 2 days (c) 16 days (d) 15 days. Q. In a garrision 500 men had provision for 60 days. A reinforcement of 500 men arrived. ... Q. A fort provisioned for 42 days, after 10 days, a reinforcement of 200 men ...

WebA fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? WebA fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? A 62 B 84 C 56 D 72 Easy Solution Verified by Toppr Correct option is B) Remaining number of men =(300−50)=250. Remaining number of …

WebFeb 22, 2024 · Solution For In a fort , 300 men had provisions for 90 days. After 20 days, 50 men left the fort. How long would the provisions last at the same rate? WebRight Answer is: SOLUTION First statement says that 300 men has 90 days food so total is 300*90=2700 After 20 days 50 men left that is 250 men still there and 70 days food of 300 men is available so total food available for 250 men is 300*70/250= 84 days . So 250 men can have food for 84 days .

WebAnswer (s) Ans 1= 120 Men - 195 days (provision left after 5 days) 30 men killed Men left - 90 Days - D so 120 x 195 = 90 x D D= 260 days Ans 2= 1200 soldiers - 24 days (after 4 days) soldiers leaving= S days= 32 so (1200-S) x 32 = 1200 x 24 S =300 soldiers By: Niharika, 1 decade ago 3 like this answer consider 1 person consumes "X" food per day

WebJan 13, 2024 · A fort has provisions for 300 men for 90 days . After 20 days , 50 men left the fort . How long would the food last at the same rate ? Advertisement Answer 3 people found it helpful tanunagar21 Answer: 84 Step-by-step explanation: Remaining number of men = (300−50)=250. Remaining number of days = (90−20)days=70 days extended front forksWebQuestion A fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? A 88 days B 48 days C 84 days D 44 days … extended from the atlantic coast to timbuktuWebRight Answer is: SOLUTION First statement says that 300 men has 90 days food so total is 300*90=2700 After 20 days 50 men left that is 250 men still there and 70 days food of … buchanan county library grundy vaWebMay 18, 2016 · A fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate. So men is inversely proportional to … buchanan county medical center iowaWebApr 4, 2024 · It is given that 150 men had food for 45 days. After 10 days, 150 men still had food for 35 days. Since, 25 men left the fort so $150 - 25 = 125$ men are left in the fort. Now, let us suppose that 125 men had food for the x number of days. We know that we have the case of indirect proportion here because as the number of men will decrease food ... buchanan county missouri assessor officeWebSolution Verified by Toppr Correct option is C) Let there be x men originally. So, x men had provisions 40 days whereas (x+500) men consumed it in 35 days Let us find the number of men in the fort as shown below: xx+500= 3540 ⇒ xx+500= 78⇒7(x+500)=8x ⇒7x+3500=8x ⇒8x−7x=3500 ⇒x=3500 Hence, there are 3500 men in the fort. Was this answer helpful? 0 0 buchanan county medical examinerWebJun 30, 2024 · 300 men x 90 days = 27000 man- days of provisions 300 men x 20 days = 6000 man days of provisions leaving 21000 man days of provisions 21000 m-d / 250m = … buchanan county missouri assessor\u0027s office