WebT i3+ Solution The correct option is D N i2+ Magnetic moment (μ) =√n(n+2)= 2.84 B.M , which corresponds to 2 unpaired electrons. Cr2+ −3d4, 4 unpaired electrons Co2+ −3d7, 3 unpaired electrons N i2+ −3d8, 2 unpaired electrons T i3+ −3d1, 1 unpaired electron Suggest Corrections 11 Similar questions Q. WebThe formula used to calculate the spin-only magnetic moment can be written in two forms; the first based on the number of unpaired electrons, n, and the second based on the electron spin quantum number, S. Since for each unpaired electron, n = 1 and S = 1 / 2 then the two formulae are clearly related and the answer obtained must be identical.
Calculate the number of unpaired electrons in Ti3+, Mn2
WebApr 10, 2024 · Best answer Electronic configuration of Cu2+ will be [Ar]3d9 so magnetic moment is given by. µ = √n(n + 2) n ( n + 2) Where n=1 (No. of unpaired electron) µ = √1(1 + 2) 1 ( 1 + 2) = √3 3 = 1.73 B.M. ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ Test WebAug 15, 2024 · The free ion Russell-Saunders ground term is 3 F (L=3 and S=1) which will give rise to a lowest energy T term in a tetrahedral field and hence the resultant magnetic moment is expected to be temperature dependent and have a direct orbital contribution. The observed values may be quite different then to the calculated spin only magnetic moment. puff barril
How many of the following ions have spin magnetic moment more …
WebCalculate the magnetic moment of Cr 3+. A 2.90 B 3.57 C 4.12 D 3.87 Medium Solution Verified by Toppr Correct option is D) Cr 3+ [Ar] 3d 3 no. of unpaired electron= 3 since μ = n(n+2) = 3(3+2) =3.87 Was this answer helpful? 0 0 Similar questions Calculate the magnetic moment of a divalent ion in aqueous solution if its atomic number is 25? Medium WebSolution: T i+2 = 1s2 2s2 2p6 3s2 3p6 3d2 unpaired electrons = 2. spin only magnetic moment (μ) = 2(2+2) = 8 B.M T i+3 = 1s2 2s2 2p6 3s2 3p6 3d1 unpaired electrons = 1 μ = 1(1+2) = 3 B.M V +2 = 1s2 2s2 2p6 3s2 3p6 3d3 μ = 3(3+2) = … WebJun 3, 2024 · Explanation: For cupric chloride, and titanium (III) chloride we gots d9 and d1 systems respectively....and an electron HOLE, i.e. Cu(I I +), is equivalent to a single electron. The spin-only moment is 1.73⋅ μB .. (you will have to look up the Bohr Magneton unit). As for cupric sulfate we got another d9 system... puff bar plus cheapest